What is the tangent of f(x)=x^2-1,(-4,15) ?

The tangent of f(x)=x^2-1,(-4,15) is y=-8x-17

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tangent of f(x)=x^2-1,(-4,15)

tangent of

f (x) = x^{2} - 1, (- 4, 15)

y = - 8 x - 17

Solution steps

Find the slope of

f (x) = x^{2} - 1 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} - 1

(- 4, 15) : m = - 8

Find the line with slope m=

- 8

and passing through

(- 4, 15) : y = - 8 x - 17

y = - 8 x - 17

ln (x + 5)

\frac{d}{d x} (cos (\frac{nπ x}{2}))

\int_{0}^{1} x \cdot 2 x d x

6^{2^{x^{2}}}

\int_{0}^{1} \frac{2 x}{( x ^{2} + 1 ) ^{3}} d x

What is the tangent of f(x)=x^2-1,(-4,15) ?
The tangent of f(x)=x^2-1,(-4,15) is y=-8x-17