What is the derivative of 1/(2x^{3/2}) ?

The derivative of 1/(2x^{3/2}) is -3/(4x^{5/2)}

What is the first derivative of 1/(2x^{3/2}) ?

The first derivative of 1/(2x^{3/2}) is -3/(4x^{5/2)}

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\frac{d}{d x} (\frac{1}{2 x ^{\frac{3}{2}}})

- \frac{3}{4 x ^{\frac{5}{2}}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x ^{\frac{3}{2}}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (\frac{1}{x ^{\frac{3}{2}}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{2} \frac{d}{d x} (x^{- \frac{3}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{2} (- \frac{3}{2} x^{- \frac{3}{2} - 1})

Simplify

\frac{1}{2} (- \frac{3}{2} x^{- \frac{3}{2} - 1}) : - \frac{3}{4 x ^{\frac{5}{2}}}

= - \frac{3}{4 x ^{\frac{5}{2}}}

x^{3}, 2

(18 y^{2} - x y) d x + x^{2} d y = 0

f (x) = x^{2} - 1, (- 4, 15)

ln (x + 5)

\frac{d}{d x} (cos (\frac{nπ x}{2}))

What is the derivative of 1/(2x^{3/2}) ?
The derivative of 1/(2x^{3/2}) is -3/(4x^{5/2)}
What is the first derivative of 1/(2x^{3/2}) ?
The first derivative of 1/(2x^{3/2}) is -3/(4x^{5/2)}