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Beliebt Rechnen >

y^'=-(1+y)/(1+x+y)

Lösung

y^{^{'}} = - \frac{1 + y}{1 + x + y}

Lösung

y = - 1 - x + x^{2} + c_{1} + 1, y = - x - x^{2} + c_{1} + 1 - 1

Schritte zur Lösung

y^{'} (x) = - \frac{1 + y}{1 + x + y}

Solve exact ODE:

y = - 1 - x + x^{2} + c_{1} + 1, y = - x - x^{2} + c_{1} + 1 - 1

y = - 1 - x + x^{2} + c_{1} + 1, y = - x - x^{2} + c_{1} + 1 - 1

Graph

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