What is the derivative of 3x^4-5x+2\sqrt[3]{x} ?

The derivative of 3x^4-5x+2\sqrt[3]{x} is (2+36x^{11/3})/(3x^{2/3)}-5

What is the first derivative of 3x^4-5x+2\sqrt[3]{x} ?

The first derivative of 3x^4-5x+2\sqrt[3]{x} is (2+36x^{11/3})/(3x^{2/3)}-5

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derivative of

\frac{2 + 36 x ^{\frac{11}{3}}}{3 x ^{\frac{2}{3}}} - 5

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (5 x) = 5

= 12 x^{3} - 5 + \frac{2}{3 x ^{\frac{2}{3}}}

Combine the fractions

\frac{2}{3 x ^{\frac{2}{3}}} + 12 x^{3} : \frac{2 + 36 x ^{\frac{11}{3}}}{3 x ^{\frac{2}{3}}}

= \frac{2 + 36 x ^{\frac{11}{3}}}{3 x ^{\frac{2}{3}}} - 5

\frac{d}{d x} (ln (1 - 6 x))

- x^{2} + 3 x + 4, at x = 1

\frac{d y}{d x} = \frac{- e ^{x}}{8}

\frac{\partial}{\partial y} (x y e^{z})

cos (7 x)

What is the derivative of 3x^4-5x+2\sqrt[3]{x} ?
The derivative of 3x^4-5x+2\sqrt[3]{x} is (2+36x^{11/3})/(3x^{2/3)}-5
What is the first derivative of 3x^4-5x+2\sqrt[3]{x} ?
The first derivative of 3x^4-5x+2\sqrt[3]{x} is (2+36x^{11/3})/(3x^{2/3)}-5