What is (\partial)/(\partial y)(xye^z) ?

The answer to (\partial)/(\partial y)(xye^z) is e^zx

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(\partial)/(\partial y)(xye^z)

\frac{\partial}{\partial y} (x y e^{z})

e^{z} x

Solution steps

\frac{\partial}{\partial y} (x y e^{z})

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x e^{z} \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= x e^{z} \cdot 1

Simplify

= e^{z} x

cos (7 x)

x \to - 1 - lim ({2 x^{2} - 5 x})

\frac{d}{d x} (3 sec^{2} (π x - 1))

f (x) = \frac{x ^{2}}{x + 1}, at x = 2

\int 20 (e^{\frac{3}{4} x} - e^{2 x}) d x

What is (\partial)/(\partial y)(xye^z) ?
The answer to (\partial)/(\partial y)(xye^z) is e^zx