What is the solution for (dy}{dx}=\frac{-e^x)/8 ?

The solution for (dy}{dx}=\frac{-e^x)/8 is y=-1/8 e^x+c_{1}

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(dy}{dx}=\frac{-e^x)/8

\frac{d y}{d x} = \frac{- e ^{x}}{8}

y = - \frac{1}{8} e^{x} + c_{1}

Solution steps

\frac{d y}{d x} = \frac{- e ^{x}}{8}

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = \frac{- e ^{x}}{8}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{- e ^{x}}{8} d x

\int \frac{- e ^{x}}{8} d x = - \frac{1}{8} e^{x} + c_{1}

y = - \frac{1}{8} e^{x} + c_{1}

\frac{\partial}{\partial y} (x y e^{z})

cos (7 x)

x \to - 1 - lim ({2 x^{2} - 5 x})

\frac{d}{d x} (3 sec^{2} (π x - 1))

f (x) = \frac{x ^{2}}{x + 1}, at x = 2

What is the solution for (dy}{dx}=\frac{-e^x)/8 ?
The solution for (dy}{dx}=\frac{-e^x)/8 is y=-1/8 e^x+c_{1}