What is (\partial)/(\partial x)(y(1-x)) ?

The answer to (\partial)/(\partial x)(y(1-x)) is -y

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(\partial)/(\partial x)(y(1-x))

\frac{\partial}{\partial x} (y (1 - x))

- y

Solution steps

\frac{\partial}{\partial x} (y (1 - x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial x} (1 - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= y (\frac{\partial}{\partial x} (1) - \frac{\partial}{\partial x} (x))

\frac{\partial}{\partial x} (1) = 0

\frac{\partial}{\partial x} (x) = 1

= y (0 - 1)

Simplify

= - y

e^{- 3 s} \cdot \frac{5}{4 s ^{2} + 16}

4 x - x^{2} (1.3)

\frac{d}{d x} (ln (e^{x} + e^{- x}))

x \to 4 + lim (\frac{2}{( x - 4 ) ^{4}})

16 y^{^{''''}} = 256 y

What is (\partial)/(\partial x)(y(1-x)) ?
The answer to (\partial)/(\partial x)(y(1-x)) is -y