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Popular >

tangent of 4x-x^2(1.3)

Solution

tangent of

4 x - x^{2} (1.3)

Solution

y = (4 - 2.6 a_{0}) x + 1.3 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 4 a_{0} - a_{0}^{2} \cdot 1.3)

Find the slope of

y = 4 x - x^{2} 1.3 : \frac{d y}{d x} = 4 - 2.6 x

Compute the slope of

y = 4 x - x^{2} 1.3

at

x = a_{0} : m = 4 - 2.6 a_{0}

Find the line with slope m=

4 - 2.6 a_{0}

and passing through

(a_{0}, 4 a_{0} - a_{0}^{2} 1.3) : y = (4 - 2.6 a_{0}) x + 1.3 a_{0}^{2}

y = (4 - 2.6 a_{0}) x + 1.3 a_{0}^{2}

Popular Examples

derivative of ln(e^x+e^{-x})

\frac{d}{d x} (ln (e^{x} + e^{- x}))

limit as x approaches 4+of 2/((x-4)^4)

x \to 4 + lim (\frac{2}{( x - 4 ) ^{4}})

16y^{''''}=256y

16 y^{^{''''}} = 256 y

integral of ln(1+1/(x^2))

\int ln (1 + \frac{1}{x ^{2}}) d x

integral of (3x+1)^{1/2}

\int (3 x + 1)^{\frac{1}{2}} d x

Frequently Asked Questions (FAQ)

What is the tangent of 4x-x^2(1.3) ?
The tangent of 4x-x^2(1.3) is y=(4-2.6a_{0})x+1.3a_{0}^2