What is the integral from 0 to 13/12 of 68/3 x ?

The integral from 0 to 13/12 of 68/3 x is 2873/216

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integral from 0 to 13/12 of 68/3 x

\int_{0}^{\frac{13}{12}} \frac{68}{3} x d x

\frac{2873}{216}

Solution steps

\int_{0}^{\frac{13}{12}} \frac{68}{3} x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{68}{3} \cdot \int_{0}^{\frac{13}{12}} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{\frac{13}{12}}

= \frac{68}{3} [\frac{x ^{2}}{2}]_{0}^{\frac{13}{12}}

Compute the boundaries:

\frac{169}{288}

= \frac{68}{3} \cdot \frac{169}{288}

Simplify

= \frac{2873}{216}

y = 2 x^{2} - 9 x + 10

\frac{d}{d x} (17.5 (x + 1)^{0.75})

k = 1 \sum \infty 8 (\frac{1}{5})^{k}

sin (x) cos (x)

\frac{8 x}{( x ^{2} + 1 )}

What is the integral from 0 to 13/12 of 68/3 x ?
The integral from 0 to 13/12 of 68/3 x is 2873/216