What is the tangent of sin(x)cos(x) ?

The tangent of sin(x)cos(x) is y=cos(2a_{0})x+sin(a_{0})cos(a_{0})-cos(2a_{0})a_{0}

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tangent of sin(x)cos(x)

tangent of

sin (x) cos (x)

y = cos (2 a_{0}) x + sin (a_{0}) cos (a_{0}) - cos (2 a_{0}) a_{0}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, sin (a_{0}) cos (a_{0}))

Find the slope of

y = sin (x) cos (x) : \frac{d y}{d x} = cos (2 x)

Compute the slope of

y = sin (x) cos (x)

x = a_{0} : m = cos (2 a_{0})

Find the line with slope m=

cos (2 a_{0})

and passing through

(a_{0}, sin (a_{0}) cos (a_{0})) : y = cos (2 a_{0}) x + sin (a_{0}) cos (a_{0}) - cos (2 a_{0}) a_{0}

y = cos (2 a_{0}) x + sin (a_{0}) cos (a_{0}) - cos (2 a_{0}) a_{0}

\frac{8 x}{( x ^{2} + 1 )}

x \to 0 - lim (ln (x))

\int \frac{8}{( 4 - t ) ^{8}} d t

y = 8 + 4 x^{2} - 2 x^{3}, (2, 8)

x \to 2 lim (x^{2} + 3 x - 4)

What is the tangent of sin(x)cos(x) ?
The tangent of sin(x)cos(x) is y=cos(2a_{0})x+sin(a_{0})cos(a_{0})-cos(2a_{0})a_{0}