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Popular >

y^'=a-by

Solution

y^{^{'}} = a - b y

Solution

y = - \frac{e ^{- b t - c_{1} b}}{b} + \frac{a}{b}

Solution steps

y^{'} (t) = a - b y (t)

Solve separable ODE:

y = - \frac{e ^{- b t - c_{1} b}}{b} + \frac{a}{b}

y = - \frac{e ^{- b t - c_{1} b}}{b} + \frac{a}{b}

Popular Examples

integral of sqrt(t)sqrt(1+t\sqrt{t)}

\int t 1 + t t d t

tangent of f(x)=sqrt(1-10x),\at x=-1 tangent of

f (x) = 1 - 10 x, at x = - 1

integral of (-1)^nx^{2n}

\int (- 1)^{n} x^{2 n} d x

limit as x approaches 0 of (x-2)^2

x \to 0 lim ((x - 2)^{2})

(d^2)/(dx^2)(xe^x)

\frac{d ^{2}}{d x ^{2}} (x e^{x})

Frequently Asked Questions (FAQ)

What is the solution for y^'=a-by ?
The solution for y^'=a-by is y=-(e^{-bt-c_{1}b})/b+a/b