What is the tangent of f(x)=sqrt(1-10x),\at x=-1 ?

The tangent of f(x)=sqrt(1-10x),\at x=-1 is y=-5/(sqrt(11))x+sqrt(11)-5/(sqrt(11))

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tangent of f(x)=sqrt(1-10x),\at x=-1

tangent of

f (x) = 1 - 10 x, at x = - 1

y = - \frac{5}{11} x + 11 - \frac{5}{11}

Solution steps

Find the tangent point:

(- 1, 11)

Find the slope of

f (x) = 1 - 10 x : \frac{df ( x )}{d x} = - \frac{5}{1 - 10 x}

Compute the slope of

f (x) = 1 - 10 x

x = - 1 : m = - \frac{5}{11}

Find the line with slope m=

- \frac{5}{11}

and passing through

(- 1, 11) : y = - \frac{5}{11} x + 11 - \frac{5}{11}

y = - \frac{5}{11} x + 11 - \frac{5}{11}

\int (- 1)^{n} x^{2 n} d x

x \to 0 lim ((x - 2)^{2})

\frac{d ^{2}}{d x ^{2}} (x e^{x})

\frac{d y}{d t} + 2 y = 0

- 3 e^{- 3 x}

What is the tangent of f(x)=sqrt(1-10x),\at x=-1 ?
The tangent of f(x)=sqrt(1-10x),\at x=-1 is y=-5/(sqrt(11))x+sqrt(11)-5/(sqrt(11))