What is the derivative of-3e^{-3x} ?

The derivative of-3e^{-3x} is 9e^{-3x}

What is the first derivative of-3e^{-3x} ?

The first derivative of-3e^{-3x} is 9e^{-3x}

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derivative of

- 3 e^{- 3 x}

9 e^{- 3 x}

Solution steps

\frac{d}{d x} (- 3 e^{- 3 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{d}{d x} (e^{- 3 x})

Apply the chain rule:

e^{- 3 x} \frac{d}{d x} (- 3 x)

= e^{- 3 x} \frac{d}{d x} (- 3 x)

\frac{d}{d x} (- 3 x) = - 3

= - 3 e^{- 3 x} (- 3)

Simplify

= 9 e^{- 3 x}

\frac{d}{d x} ((2 x - 3)^{2})

\int \frac{sin ( 5 ln ( t ) )}{t} d t

x \to 7 - lim (- \frac{2}{7 - x})

n = 3 \sum \infty \frac{n ^{2}}{e ^{n}}

0.03 x^{2} - 4 x + 3 x^{0.8} - 5000

What is the derivative of-3e^{-3x} ?
The derivative of-3e^{-3x} is 9e^{-3x}
What is the first derivative of-3e^{-3x} ?
The first derivative of-3e^{-3x} is 9e^{-3x}