What is the derivative of 2x+sin(x) ?

The derivative of 2x+sin(x) is 2+cos(x)

What is the first derivative of 2x+sin(x) ?

The first derivative of 2x+sin(x) is 2+cos(x)

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\frac{d}{d x} (2 x + sin (x))

2 + cos (x)

Solution steps

\frac{d}{d x} (2 x + sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (sin (x))

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (sin (x)) = cos (x)

= 2 + cos (x)

\frac{d}{d x} (\frac{x ^{2} cos ( x )}{tan ( x )})

\int (z + 1) e^{z} d z

x \to 0 + lim (\frac{2}{x} - \frac{1}{ln ( x )})

\int_{1}^{\infty} e^{- 2 x} d x

\frac{\partial}{\partial x} (x^{4 y})

What is the derivative of 2x+sin(x) ?
The derivative of 2x+sin(x) is 2+cos(x)
What is the first derivative of 2x+sin(x) ?
The first derivative of 2x+sin(x) is 2+cos(x)