What is the limit as x approaches 0+of 2/x-1/(ln(x)) ?

The limit as x approaches 0+of 2/x-1/(ln(x)) is infinity

Popular >

limit as x approaches 0+of 2/x-1/(ln(x))

x \to 0 + lim (\frac{2}{x} - \frac{1}{ln ( x )})

\infty

Solution steps

x \to 0 + lim (\frac{2}{x} - \frac{1}{ln ( x )})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 + lim (\frac{2}{x}) - x \to 0 + lim (\frac{1}{ln ( x )})

x \to 0 + lim (\frac{2}{x}) = \infty

x \to 0 + lim (\frac{1}{ln ( x )}) = 0

= \infty - 0

Apply Infinity Property:

\infty - c = \infty

= \infty

\int_{1}^{\infty} e^{- 2 x} d x

\frac{\partial}{\partial x} (x^{4 y})

x y^{^{'}} = 2 y + 7 x

\frac{\partial}{\partial x} (x^{3} + 2 y^{2} + 8 x + 5 y + 5 x y)

y^{^{''}} + 9 y^{^{'}} = 40 e^{1 t}

What is the limit as x approaches 0+of 2/x-1/(ln(x)) ?
The limit as x approaches 0+of 2/x-1/(ln(x)) is infinity