What is the derivative of 2x^{3x} ?

The derivative of 2x^{3x} is 6x^{3x}(ln(x)+1)

What is the first derivative of 2x^{3x} ?

The first derivative of 2x^{3x} is 6x^{3x}(ln(x)+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (2 x^{3 x})

6 x^{3 x} (ln (x) + 1)

Solution steps

\frac{d}{d x} (2 x^{3 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{3 x})

Apply exponent rule:

a^{b} = e^{b l n (a)}

x^{3 x} = e^{3 x l n (x)}

= 2 \frac{d}{d x} (e^{3 x l n (x)})

Apply the chain rule:

e^{3 x l n (x)} \frac{d}{d x} (3 x ln (x))

= e^{3 x l n (x)} \frac{d}{d x} (3 x ln (x))

\frac{d}{d x} (3 x ln (x)) = 3 (ln (x) + 1)

= 2 e^{3 x l n (x)} \cdot 3 (ln (x) + 1)

Simplify

2 e^{3 x l n (x)} \cdot 3 (ln (x) + 1) : 6 x^{3 x} (ln (x) + 1)

= 6 x^{3 x} (ln (x) + 1)

\frac{\partial}{\partial x} (\frac{1}{2} (x - y)^{2})

t y^{^{'}} + 2 y = 4 t^{2}

x \to - 2 lim (\frac{x}{x ^{2} - 4})

\frac{d}{d x} (2 sin^{3} (x) - 3 cos^{2} (x))

\int \frac{5}{32} x^{4} d x

What is the derivative of 2x^{3x} ?
The derivative of 2x^{3x} is 6x^{3x}(ln(x)+1)
What is the first derivative of 2x^{3x} ?
The first derivative of 2x^{3x} is 6x^{3x}(ln(x)+1)