What is the derivative of 3x^2-3x+4 ?

The derivative of 3x^2-3x+4 is 6x-3

What is the first derivative of 3x^2-3x+4 ?

The first derivative of 3x^2-3x+4 is 6x-3

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\frac{d}{d x} (3 x^{2} - 3 x + 4)

6 x - 3

Solution steps

\frac{d}{d x} (3 x^{2} - 3 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (4)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (4) = 0

= 6 x - 3 + 0

Simplify

= 6 x - 3

n = 0 \sum \infty (- 0.3)^{n}

x^{3} - x^{2} - 4 x - 4, 2 x - 4

\frac{d}{d x} (\frac{8 x ^{2} + 4 x + 4}{x})

5 x^{\frac{3}{2}}

e^{\frac{x ^{2}}{2}}

What is the derivative of 3x^2-3x+4 ?
The derivative of 3x^2-3x+4 is 6x-3
What is the first derivative of 3x^2-3x+4 ?
The first derivative of 3x^2-3x+4 is 6x-3