What is area x^3-x^2-4x-4,2x-4 ?

The answer to area x^3-x^2-4x-4,2x-4 is 253/12

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area x^3-x^2-4x-4,2x-4

area

x^{3} - x^{2} - 4 x - 4, 2 x - 4

\frac{253}{12}

Solution steps

Apply the area formula:

\int_{- 2}^{3} x^{3} - x^{2} - 4 x - 4 - (2 x - 4) d x

Solve

\int_{- 2}^{3} x^{3} - x^{2} - 4 x - 4 - (2 x - 4) d x : \frac{253}{12}

The area is:

= \frac{253}{12}

\frac{d}{d x} (\frac{8 x ^{2} + 4 x + 4}{x})

5 x^{\frac{3}{2}}

e^{\frac{x ^{2}}{2}}

x, x

f (x) = \frac{1}{- 2 + ( 3 x + 1 ) ^{2}}