What is the derivative of (8x^2+4x+4/(sqrt(x))) ?

The derivative of (8x^2+4x+4/(sqrt(x))) is (12x^2+2x-2)/(xsqrt(x))

What is the first derivative of (8x^2+4x+4/(sqrt(x))) ?

The first derivative of (8x^2+4x+4/(sqrt(x))) is (12x^2+2x-2)/(xsqrt(x))

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\frac{d}{d x} (\frac{8 x ^{2} + 4 x + 4}{x})

\frac{12 x ^{2} + 2 x - 2}{x x}

Solution steps

\frac{d}{d x} (\frac{8 x ^{2} + 4 x + 4}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 8 x ^{2} + 4 x + 4 ) x - \frac{d}{d x} ( x ) ( 8 x ^{2} + 4 x + 4 )}{( x ) ^{2}}

\frac{d}{d x} (8 x^{2} + 4 x + 4) = 16 x + 4

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{( 16 x + 4 ) x - \frac{1}{2 x} ( 8 x ^{2} + 4 x + 4 )}{( x ) ^{2}}

Simplify

\frac{( 16 x + 4 ) x - \frac{1}{2 x} ( 8 x ^{2} + 4 x + 4 )}{( x ) ^{2}} : \frac{12 x ^{2} + 2 x - 2}{x x}

= \frac{12 x ^{2} + 2 x - 2}{x x}

5 x^{\frac{3}{2}}

e^{\frac{x ^{2}}{2}}

x, x

f (x) = \frac{1}{- 2 + ( 3 x + 1 ) ^{2}}

\int (5 x^{2} + 1) 5 x^{3} + 3 x - 2 d x

What is the derivative of (8x^2+4x+4/(sqrt(x))) ?
The derivative of (8x^2+4x+4/(sqrt(x))) is (12x^2+2x-2)/(xsqrt(x))
What is the first derivative of (8x^2+4x+4/(sqrt(x))) ?
The first derivative of (8x^2+4x+4/(sqrt(x))) is (12x^2+2x-2)/(xsqrt(x))