What is the integral of (5x^2+1)sqrt(5x^3+3x-2) ?

The integral of (5x^2+1)sqrt(5x^3+3x-2) is 2/9 (5x^3+3x-2)^{3/2}+C

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integral of (5x^2+1)sqrt(5x^3+3x-2)

\int (5 x^{2} + 1) 5 x^{3} + 3 x - 2 d x

\frac{2}{9} (5 x^{3} + 3 x - 2)^{\frac{3}{2}} + C

Solution steps

\int (5 x^{2} + 1) 5 x^{3} + 3 x - 2 d x

Apply u-substitution

: \int \frac{u}{3} d u

= \int \frac{u}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{1}{3} \cdot \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = 5 x^{3} + 3 x - 2

= \frac{1}{3} \cdot \frac{2}{3} (5 x^{3} + 3 x - 2)^{\frac{3}{2}}

Simplify

\frac{1}{3} \cdot \frac{2}{3} (5 x^{3} + 3 x - 2)^{\frac{3}{2}} : \frac{2}{9} (5 x^{3} + 3 x - 2)^{\frac{3}{2}}

= \frac{2}{9} (5 x^{3} + 3 x - 2)^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{9} (5 x^{3} + 3 x - 2)^{\frac{3}{2}} + C

\frac{d}{d x} (sinh^{2} (x))

\int x^{2} - 4 x + 3 d x

\int \frac{y}{3 y + 1} d y

\frac{d y}{d x} = 3 cos (x) y, y (\frac{π}{2}) = - 2

\frac{d}{d x} ((x^{2}) (\frac{2}{x ^{2}} + \frac{5}{x ^{3}}))

What is the integral of (5x^2+1)sqrt(5x^3+3x-2) ?
The integral of (5x^2+1)sqrt(5x^3+3x-2) is 2/9 (5x^3+3x-2)^{3/2}+C