What is the derivative of x^3+7x-1 ?

The derivative of x^3+7x-1 is 3x^2+7

What is the first derivative of x^3+7x-1 ?

The first derivative of x^3+7x-1 is 3x^2+7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x^{3} + 7 x - 1)

3 x^{2} + 7

Solution steps

\frac{d}{d x} (x^{3} + 7 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (7 x) - \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (7 x) = 7

\frac{d}{d x} (1) = 0

= 3 x^{2} + 7 - 0

Simplify

= 3 x^{2} + 7

f (x) = x (x^{2} + 6)

\int - 2 sin^{3} (x) cos^{2} (x) d x

\frac{d}{d x} (e^{x + x^{2} + 1})

x - 8

\frac{d y}{d x} + \frac{1}{x} y = 8 x^{2}

What is the derivative of x^3+7x-1 ?
The derivative of x^3+7x-1 is 3x^2+7
What is the first derivative of x^3+7x-1 ?
The first derivative of x^3+7x-1 is 3x^2+7