What is the derivative of f(x)=x(x^2+6) ?

The derivative of f(x)=x(x^2+6) is 3x^2+6

What is the first derivative of f(x)=x(x^2+6) ?

The first derivative of f(x)=x(x^2+6) is 3x^2+6

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derivative of

f (x) = x (x^{2} + 6)

3 x^{2} + 6

Solution steps

\frac{d}{d x} (x (x^{2} + 6))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = x^{2} + 6

= \frac{d x}{d x} (x^{2} + 6) + \frac{d}{d x} (x^{2} + 6) x

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2} + 6) = 2 x

= 1 \cdot (x^{2} + 6) + 2 xx

Simplify

1 \cdot (x^{2} + 6) + 2 xx : 3 x^{2} + 6

= 3 x^{2} + 6

\int - 2 sin^{3} (x) cos^{2} (x) d x

\frac{d}{d x} (e^{x + x^{2} + 1})

x - 8

\frac{d y}{d x} + \frac{1}{x} y = 8 x^{2}

x \to - 2 - lim (\frac{4}{x + 2})

What is the derivative of f(x)=x(x^2+6) ?
The derivative of f(x)=x(x^2+6) is 3x^2+6
What is the first derivative of f(x)=x(x^2+6) ?
The first derivative of f(x)=x(x^2+6) is 3x^2+6