What is (\partial)/(\partial x)(xsin(y)sin(z)) ?

The answer to (\partial)/(\partial x)(xsin(y)sin(z)) is sin(y)sin(z)

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(\partial)/(\partial x)(xsin(y)sin(z))

\frac{\partial}{\partial x} (x sin (y) sin (z))

sin (y) sin (z)

Solution steps

\frac{\partial}{\partial x} (x sin (y) sin (z))

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (y) sin (z) \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= sin (y) sin (z) \cdot 1

Simplify

= sin (y) sin (z)

\int (x^{2} + 1)^{\frac{1}{2}} x d x

\int (- 3 x + 4) e - x d x

\int_{0}^{\frac{π}{2}} 7 cos^{2} (x) d x

y = x^{2}, y = - x^{2} + 18 x

f (x) = c x^{- 7}

What is (\partial)/(\partial x)(xsin(y)sin(z)) ?
The answer to (\partial)/(\partial x)(xsin(y)sin(z)) is sin(y)sin(z)