derivada de 3/(2x+(4x)/5)

Solución

\frac{d}{d x} (\frac{3}{2 x} + \frac{4 x}{5})

- \frac{3}{2 x ^{2}} + \frac{4}{5}

Pasos de solución

\frac{d}{d x} (\frac{3}{2 x} + \frac{4 x}{5})

Aplicar la regla de la suma/diferencia:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{3}{2 x}) + \frac{d}{d x} (\frac{4 x}{5})

\frac{d}{d x} (\frac{3}{2 x}) = - \frac{3}{2 x ^{2}}

\frac{d}{d x} (\frac{4 x}{5}) = \frac{4}{5}

= - \frac{3}{2 x ^{2}} + \frac{4}{5}

y = \frac{3 x + 4}{2 x - 1}

f (x) = (x^{6} - 4 x^{2} + 2) ln (x)

\int \frac{2}{3} t^{\frac{3}{2}} - 8 sin (t) + C d t

\frac{\partial}{\partial x} (e^{x^{2} + y} - 2 x y)

y^{^{'}} = x y (y + 2)