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Popular >

y^'=xy(y+2)

Solution

y^{^{'}} = x y (y + 2)

Solution

y = \frac{2}{e ^{- x^{2} - c_{1}} - 1}

Solution steps

y^{'} (x) = x y (y + 2)

Solve Bernoulli ODE:

y = \frac{2}{e ^{- x^{2} - c_{1}} - 1}

y = \frac{2}{e ^{- x^{2} - c_{1}} - 1}

Popular Examples

sum from n=1 to infinity of 9/(n^3)

n = 1 \sum \infty \frac{9}{n ^{3}}

sum from n=0 to infinity of 4(3/4)^n

n = 0 \sum \infty 4 (\frac{3}{4})^{n}

derivative of (ln(x+2)/(4x^{-2)})

\frac{d}{d x} (\frac{ln ( x + 2 )}{4 x ^{- 2}})

inverse oflaplace (2s+1)/(s^3)inverse laplace

\frac{2 s + 1}{s ^{3}}

derivative of h(x)=(x^2+4x+1)/(3x+5)derivative of

h (x) = \frac{x ^{2} + 4 x + 1}{3 x + 5}

Frequently Asked Questions (FAQ)

What is the solution for y^'=xy(y+2) ?
The solution for y^'=xy(y+2) is y= 2/(e^{-x^2-c_{1)}-1}