What is (\partial)/(\partial x)(e^{x^2+y}-2xy) ?

The answer to (\partial)/(\partial x)(e^{x^2+y}-2xy) is e^{x^2+y}*2x-2y

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(\partial)/(\partial x)(e^{x^2+y}-2xy)

\frac{\partial}{\partial x} (e^{x^{2} + y} - 2 x y)

e^{x^{2} + y} \cdot 2 x - 2 y

Solution steps

\frac{\partial}{\partial x} (e^{x^{2} + y} - 2 x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (e^{x^{2} + y}) - \frac{\partial}{\partial x} (2 x y)

\frac{\partial}{\partial x} (e^{x^{2} + y}) = e^{x^{2} + y} \cdot 2 x

\frac{\partial}{\partial x} (2 x y) = 2 y

= e^{x^{2} + y} \cdot 2 x - 2 y

y^{^{'}} = x y (y + 2)

n = 1 \sum \infty \frac{9}{n ^{3}}

n = 0 \sum \infty 4 (\frac{3}{4})^{n}

\frac{d}{d x} (\frac{ln ( x + 2 )}{4 x ^{- 2}})

\frac{2 s + 1}{s ^{3}}

What is (\partial)/(\partial x)(e^{x^2+y}-2xy) ?
The answer to (\partial)/(\partial x)(e^{x^2+y}-2xy) is e^{x^2+y}*2x-2y