What is the integral of sqrt(3x-12) ?

The integral of sqrt(3x-12) is 2/9 (3x-12)^{3/2}+C

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integral of sqrt(3x-12)

\int 3 x - 12 d x

\frac{2}{9} (3 x - 12)^{\frac{3}{2}} + C

Solution steps

\int 3 x - 12 d x

Apply u-substitution

: \int \frac{u}{3} d u

= \int \frac{u}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{1}{3} \cdot \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = 3 x - 12

= \frac{1}{3} \cdot \frac{2}{3} (3 x - 12)^{\frac{3}{2}}

Simplify

\frac{1}{3} \cdot \frac{2}{3} (3 x - 12)^{\frac{3}{2}} : \frac{2}{9} (3 x - 12)^{\frac{3}{2}}

= \frac{2}{9} (3 x - 12)^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{9} (3 x - 12)^{\frac{3}{2}} + C

\frac{d}{d x} (\frac{3}{2 x} + \frac{4 x}{5})

y = \frac{3 x + 4}{2 x - 1}

f (x) = (x^{6} - 4 x^{2} + 2) ln (x)

\int \frac{2}{3} t^{\frac{3}{2}} - 8 sin (t) + C d t

\frac{\partial}{\partial x} (e^{x^{2} + y} - 2 x y)

What is the integral of sqrt(3x-12) ?
The integral of sqrt(3x-12) is 2/9 (3x-12)^{3/2}+C