d/(dt)(e^{3tsin(2t)})

Lösung

\frac{d}{d t} (e^{3 t s i n (2 t)})

e^{3 t s i n (2 t)} \cdot 3 (sin (2 t) + 2 t cos (2 t))

Schritte zur Lösung

\frac{d}{d t} (e^{3 t s i n (2 t)})

Wende die Kettenregel an:

e^{3 t s i n (2 t)} \frac{d}{d t} (3 t sin (2 t))

= e^{3 t s i n (2 t)} \frac{d}{d t} (3 t sin (2 t))

\frac{d}{d t} (3 t sin (2 t)) = 3 (sin (2 t) + 2 t cos (2 t))

= e^{3 t s i n (2 t)} \cdot 3 (sin (2 t) + 2 t cos (2 t))

x^{2} y^{^{''}} - 3 x y^{^{'}} + 5 y = 0, y (1) = - 1, y^{^{'}} (1) = 4

\int sin (2 x) \cdot sin (x) d x

\int \frac{5 e ^{x}}{e ^{2 x} + 8 e ^{x} + 16} d x

\int (\frac{7}{x ^{4}}) d x

\int_{t}^{1} \frac{1}{x ^{2}} d x