What is the solution for y^{''}-y=0,y(0)=0,y^'(0)=5 ?

The solution for y^{''}-y=0,y(0)=0,y^'(0)=5 is y= 5/2 e^t-5/2 e^{-t}

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y^{''}-y=0,y(0)=0,y^'(0)=5

y^{^{''}} - y = 0, y (0) = 0, y^{^{'}} (0) = 5

y = \frac{5}{2} e^{t} - \frac{5}{2} e^{- t}

Solution steps

y^{''} (t) - y = 0

Solve linear ODE:

y = \frac{5}{2} e^{t} - \frac{5}{2} e^{- t}

y = \frac{5}{2} e^{t} - \frac{5}{2} e^{- t}

What is the solution for y^{''}-y=0,y(0)=0,y^'(0)=5 ?
The solution for y^{''}-y=0,y(0)=0,y^'(0)=5 is y= 5/2 e^t-5/2 e^{-t}