What is the solution for y^{''}+2y=cos(x) ?

The solution for y^{''}+2y=cos(x) is y=c_{1}cos(sqrt(2)x)+c_{2}sin(sqrt(2)x)+cos(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}+2y=cos(x)

y^{^{''}} + 2 y = cos (x)

y = c_{1} cos (2 x) + c_{2} sin (2 x) + cos (x)

Solution steps

y^{''} (x) + 2 y = cos (x)

Solve linear ODE:

y = c_{1} cos (2 x) + c_{2} sin (2 x) + cos (x)

y = c_{1} cos (2 x) + c_{2} sin (2 x) + cos (x)

What is the solution for y^{''}+2y=cos(x) ?
The solution for y^{''}+2y=cos(x) is y=c_{1}cos(sqrt(2)x)+c_{2}sin(sqrt(2)x)+cos(x)