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Beliebt Rechnen >

q^{''}+20q^'+100q=24,q(0)=0,q^'(0)=0

Lösung

q^{^{''}} + 20 q^{^{'}} + 100 q = 24, q (0) = 0, q^{^{'}} (0) = 0

Lösung

q (t) = - \frac{6}{25} e^{- 10 t} - \frac{12 e ^{- 10 t} t}{5} + \frac{6}{25}

Schritte zur Lösung

q^{''} (t) + 20 q^{'} (t) + 100 q (t) = 24

Solve linear ODE:

q (t) = - \frac{6}{25} e^{- 10 t} - \frac{12 e ^{- 10 t} t}{5} + \frac{6}{25}

q (t) = - \frac{6}{25} e^{- 10 t} - \frac{12 e ^{- 10 t} t}{5} + \frac{6}{25}

Graph

Beliebte Beispiele

(D^2+1)y=e^{ix}

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y^{^{''}} - 2 y^{^{'}} - 3 y = t^{2} + 3 e^{- t} cos (4 t)

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y^{^{'''}} + 4 y^{^{'}} = sec (2 t)

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y^{''}-2y^'+y=2sin(x)

y^{^{''}} - 2 y^{^{'}} + y = 2 sin (x)