en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=x^3,x=-1

Solution

area

y = x^{3}, x = - 1

Solution

\frac{1}{4}

+1

Solution steps

Apply the area formula:

\int_{- 1}^{0} x^{3} d x

Solve

\int_{- 1}^{0} x^{3} d x : \frac{1}{4}

The area is:

= \frac{1}{4}

Popular Examples

tangent of f(x)=(x^3+1)(x^2-2),\at x=2 tangent of

f (x) = (x^{3} + 1) (x^{2} - 2), at x = 2

tangent of f(x)=(x-4)(3-x)^3,\at x=5 tangent of

f (x) = (x - 4) (3 - x)^{3}, at x = 5

integral of x^2(3x+x^{-3})

\int x^{2} (3 x + x^{- 3}) d x

integral of sin(-3x)

\int sin (- 3 x) d x

limit as t approaches pi of-9sin(-t/2)

t \to π lim (- 9 sin (- \frac{t}{2}))

Frequently Asked Questions (FAQ)

What is area y=x^3,x=-1 ?
The answer to area y=x^3,x=-1 is 1/4