2y^{''}+3y^'-4y=5e^{3x}

Lösung

2 y^{^{''}} + 3 y^{^{'}} - 4 y = 5 e^{3 x}

y = c_{1} e^{\frac{( - 3 + 41 ) x}{4}} + c_{2} e^{\frac{( - 3 - 41 ) x}{4}} + \frac{5}{23} e^{3 x}

Schritte zur Lösung

2 y^{''} (x) + 3 y^{'} (x) - 4 y = 5 e^{3 x}

Solve linear ODE:

y = c_{1} e^{\frac{( - 3 + 41 ) x}{4}} + c_{2} e^{\frac{( - 3 - 41 ) x}{4}} + \frac{5}{23} e^{3 x}

y = c_{1} e^{\frac{( - 3 + 41 ) x}{4}} + c_{2} e^{\frac{( - 3 - 41 ) x}{4}} + \frac{5}{23} e^{3 x}

n = 1 \sum \infty \frac{( 3 x - 2 ) ^{n}}{n}

n = 1 \sum \infty \frac{7 n}{5 n + 1}

\int 20 x sec^{2} (x) d x

\int \frac{1}{x \cdot x - 1} d x

\frac{\partial}{\partial x} (\frac{x + 4}{y + 4})