integral of (10x^4+2x+1)

Lösung

\int (10 x^{4} + 2 x + 1) d x

2 x^{5} + x^{2} + x + C

Schritte zur Lösung

\int 10 x^{4} + 2 x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 10 x^{4} d x + \int 2 x d x + \int 1 d x

\int 10 x^{4} d x = 2 x^{5}

\int 2 x d x = x^{2}

\int 1 d x = x

= 2 x^{5} + x^{2} + x

Füge eine Konstante zur Lösung hinzu

= 2 x^{5} + x^{2} + x + C

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