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Beliebt Rechnen >

4y^{''}+28y^'+49y=0

Lösung

4 y^{^{''}} + 28 y^{^{'}} + 49 y = 0

Lösung

y = c_{1} e^{- \frac{7 t}{2}} + c_{2} e^{- \frac{7 t}{2}} t

Schritte zur Lösung

4 y^{''} (t) + 28 y^{'} (t) + 49 y = 0

Solve linear ODE:

y = c_{1} e^{- \frac{7 t}{2}} + c_{2} e^{- \frac{7 t}{2}} t

y = c_{1} e^{- \frac{7 t}{2}} + c_{2} e^{- \frac{7 t}{2}} t

Graph

Beliebte Beispiele

derivative f(t)=e^{t+9}

d er i v a t i v e f (t) = e^{t + 9}

derivative of e^{x^9}

\frac{d}{d x} (e^{x^{9}})

(\partial)/(\partial x)(z*cos(y*x))

\frac{\partial}{\partial x} (z \cdot cos (y \cdot x))

y^{^{'}} = 2 y + e^{x}

derivative 4cos(cos(x))

d er i v a t i v e 4 cos (cos (x))