What is the derivative of y=(5x+4)^3 ?

The derivative of y=(5x+4)^3 is 15(5x+4)^2

What is the first derivative of y=(5x+4)^3 ?

The first derivative of y=(5x+4)^3 is 15(5x+4)^2

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derivative of

y = (5 x + 4)^{3}

15 (5 x + 4)^{2}

Solution steps

\frac{d}{d x} ((5 x + 4)^{3})

Apply the chain rule:

3 (5 x + 4)^{2} \frac{d}{d x} (5 x + 4)

= 3 (5 x + 4)^{2} \frac{d}{d x} (5 x + 4)

\frac{d}{d x} (5 x + 4) = 5

= 3 (5 x + 4)^{2} \cdot 5

Simplify

= 15 (5 x + 4)^{2}

1 - y^{^{'}} = cos (y)

\int_{2}^{3} \frac{3}{3 - x} d x

x = 0, y = - 1 + \frac{x ^{2}}{4}, y = 2 + \frac{x}{4}

\frac{\partial}{\partial x} (- 45 x y - 5 x^{2} y - 5 x y^{2})

- x^{2} + 12 x - 32

What is the derivative of y=(5x+4)^3 ?
The derivative of y=(5x+4)^3 is 15(5x+4)^2
What is the first derivative of y=(5x+4)^3 ?
The first derivative of y=(5x+4)^3 is 15(5x+4)^2