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Popular >

1-y^'=cos(y)

Solution

1 - y^{^{'}} = cos (y)

Solution

y = 2 arccot (- t - c_{1}) + 2 πn

Solution steps

1 - y^{'} (t) = cos (y)

Solve separable ODE:

y = 2 arccot (- t - c_{1}) + 2 πn

y = 2 arccot (- t - c_{1}) + 2 πn

Popular Examples

integral from 2 to 3 of 3/(sqrt(3-x))

\int_{2}^{3} \frac{3}{3 - x} d x

area x=0,y=-1+(x^2)/4 ,y=2+x/4 area

x = 0, y = - 1 + \frac{x ^{2}}{4}, y = 2 + \frac{x}{4}

(\partial)/(\partial x)(-45xy-5x^2y-5xy^2)

\frac{\partial}{\partial x} (- 45 x y - 5 x^{2} y - 5 x y^{2})

derivative of sqrt(-x^2+12x-32)derivative of

- x^{2} + 12 x - 32

limit as x approaches-2 of |x-2|

x \to - 2 lim (∣ x - 2 ∣)

Frequently Asked Questions (FAQ)

What is the solution for 1-y^'=cos(y) ?
The solution for 1-y^'=cos(y) is y=2arccot(-t-c_{1})+2pin