What is area x=0,y=-1+(x^2)/4 ,y=2+x/4 ?

The answer to area x=0,y=-1+(x^2)/4 ,y=2+x/4 is 343/24

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area x=0,y=-1+(x^2)/4 ,y=2+x/4

area

x = 0, y = - 1 + \frac{x ^{2}}{4}, y = 2 + \frac{x}{4}

\frac{343}{24}

Solution steps

Apply the area formula:

\int_{- 3}^{4} - 1 + \frac{x ^{2}}{4} - (2 + \frac{x}{4}) d x

Solve

\int_{- 3}^{4} - 1 + \frac{x ^{2}}{4} - (2 + \frac{x}{4}) d x : \frac{343}{24}

The area is:

= \frac{343}{24}

\frac{\partial}{\partial x} (- 45 x y - 5 x^{2} y - 5 x y^{2})

- x^{2} + 12 x - 32

x \to - 2 lim (∣ x - 2 ∣)

\int (4) d x

\frac{d}{d x} \frac{( x ^{2} - 4 ) ^{\frac{3}{2}}}{6}

What is area x=0,y=-1+(x^2)/4 ,y=2+x/4 ?
The answer to area x=0,y=-1+(x^2)/4 ,y=2+x/4 is 343/24