What is the integral of sin(3x)sin(2x) ?

The integral of sin(3x)sin(2x) is 1/2 (-1/5 sin(5x)+sin(x))+C

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integral of sin(3x)sin(2x)

\int sin (3 x) sin (2 x) d x

\frac{1}{2} (- \frac{1}{5} sin (5 x) + sin (x)) + C

Solution steps

\int sin (3 x) sin (2 x) d x

Rewrite using trig identities

= \int \frac{1}{2} (- cos (5 x) + cos (x)) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int - cos (5 x) + cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (- \int cos (5 x) d x + \int cos (x) d x)

\int cos (5 x) d x = \frac{1}{5} sin (5 x)

\int cos (x) d x = sin (x)

= \frac{1}{2} (- \frac{1}{5} sin (5 x) + sin (x))

Add a constant to the solution

= \frac{1}{2} (- \frac{1}{5} sin (5 x) + sin (x)) + C

x^{2} - 8 x + 16

\int_{2}^{\infty} \frac{1}{x ^{3}} d x

y^{^{'}} - 2 y = 3 e^{t}

15000 + 250 0^{t}

\frac{\partial}{\partial x} (\frac{2}{1 + x ^{3}})

What is the integral of sin(3x)sin(2x) ?
The integral of sin(3x)sin(2x) is 1/2 (-1/5 sin(5x)+sin(x))+C