What is the integral from 2 to infinity of 1/(x^3) ?

The integral from 2 to infinity of 1/(x^3) is 1/8

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integral from 2 to infinity of 1/(x^3)

\int_{2}^{\infty} \frac{1}{x ^{3}} d x

\frac{1}{8}

Decimal Notation

0.125

Solution steps

\int_{2}^{\infty} \frac{1}{x ^{3}} d x

Compute the indefinite integral:

\int \frac{1}{x ^{3}} d x = - \frac{1}{2 x ^{2}} + C

Compute the boundaries:

\int_{2}^{\infty} \frac{1}{x ^{3}} d x = 0 - (- \frac{1}{8})

= 0 - (- \frac{1}{8})

Simplify

= \frac{1}{8}

y^{^{'}} - 2 y = 3 e^{t}

15000 + 250 0^{t}

\frac{\partial}{\partial x} (\frac{2}{1 + x ^{3}})

\int x ln^{2} (d) x d x

\frac{d}{d x} (arccot (x^{2}))

What is the integral from 2 to infinity of 1/(x^3) ?
The integral from 2 to infinity of 1/(x^3) is 1/8