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Popular >

derivative of 15000+2500^t

Solution

derivative of

15000 + 250 0^{t}

Solution

ln (50) \cdot 62 5^{t} \cdot 2^{2 t + 1}

Solution steps

\frac{d}{d t} (15000 + 250 0^{t})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (15000) + \frac{d}{d t} (250 0^{t})

\frac{d}{d t} (15000) = 0

\frac{d}{d t} (250 0^{t}) = ln (50) \cdot 62 5^{t} \cdot 2^{2 t + 1}

= 0 + ln (50) \cdot 62 5^{t} \cdot 2^{2 t + 1}

Simplify

= ln (50) \cdot 62 5^{t} \cdot 2^{2 t + 1}

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\int x ln^{2} (d) x d x

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\frac{d}{d x} (3 e^{- 5 x})

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Frequently Asked Questions (FAQ)

What is the derivative of 15000+2500^t ?
The derivative of 15000+2500^t is ln(50)*625^t*2^{2t+1}
What is the first derivative of 15000+2500^t ?
The first derivative of 15000+2500^t is ln(50)*625^t*2^{2t+1}