What is the solution for 3x^2e^y+(x^3e^y-1)(dy)/(dx)=0 ?

The solution for 3x^2e^y+(x^3e^y-1)(dy)/(dx)=0 is y=-\W(-(x^3)/(e^{c_{1)}})-c_{1}

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3x^2e^y+(x^3e^y-1)(dy)/(dx)=0

3 x^{2} e^{y} + (x^{3} e^{y} - 1) \frac{d y}{d x} = 0

y = - W (- \frac{x ^{3}}{e ^{c_{1}}}) - c_{1}

Solution steps

3 x^{2} e^{y} + (x^{3} e^{y} - 1) \frac{d y}{d x} = 0

Solve exact ODE:

y = - W (- \frac{x ^{3}}{e ^{c_{1}}}) - c_{1}

y = - W (- \frac{x ^{3}}{e ^{c_{1}}}) - c_{1}

f (x) = x sin (π x), at x = 1

f (x) = \frac{3}{x}, at x = \frac{1}{4}

4 x - 3 y + y^{^{'}} (2 y - 3 x) = 0

t \to 0 lim (\frac{4}{t} - \frac{4}{t ^{2} - t})

\frac{\partial}{\partial x} (- 3 x - 1 e^{x} cos (y))

What is the solution for 3x^2e^y+(x^3e^y-1)(dy)/(dx)=0 ?
The solution for 3x^2e^y+(x^3e^y-1)(dy)/(dx)=0 is y=-\W(-(x^3)/(e^{c_{1)}})-c_{1}