What is the tangent of f(x)=xsin(pix),\at x=1 ?

The tangent of f(x)=xsin(pix),\at x=1 is y=-pix+pi

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tangent of f(x)=xsin(pix),\at x=1

tangent of

f (x) = x sin (π x), at x = 1

y = - π x + π

Solution steps

Find the tangent point:

(1, 0)

Find the slope of

f (x) = x sin (π x) : \frac{df ( x )}{d x} = sin (π x) + π x cos (π x)

Compute the slope of

f (x) = x sin (π x)

x = 1 : m = - π

Find the line with slope m=

- π

and passing through

(1, 0) : y = - π x + π

y = - π x + π

f (x) = \frac{3}{x}, at x = \frac{1}{4}

4 x - 3 y + y^{^{'}} (2 y - 3 x) = 0

t \to 0 lim (\frac{4}{t} - \frac{4}{t ^{2} - t})

\frac{\partial}{\partial x} (- 3 x - 1 e^{x} cos (y))

\int x e^{- x^{2}} d x

What is the tangent of f(x)=xsin(pix),\at x=1 ?
The tangent of f(x)=xsin(pix),\at x=1 is y=-pix+pi