What is the limit as t approaches 0 of 4/t-4/(t^2-t) ?

The limit as t approaches 0 of 4/t-4/(t^2-t) is diverges

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limit as t approaches 0 of 4/t-4/(t^2-t)

t \to 0 lim (\frac{4}{t} - \frac{4}{t ^{2} - t})

diverges

Solution steps

t \to 0 lim (\frac{4}{t} - \frac{4}{t ^{2} - t})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

t \to 0 + lim (\frac{4}{t} - \frac{4}{t ^{2} - t}) = \infty

t \to 0 - lim (\frac{4}{t} - \frac{4}{t ^{2} - t}) = - \infty

= diverges

\frac{\partial}{\partial x} (- 3 x - 1 e^{x} cos (y))

\int x e^{- x^{2}} d x

\int \frac{y + 1}{y} d y

f (x) = \frac{1}{x + 2}

\frac{\partial}{\partial x} (\frac{x}{3 + y})

What is the limit as t approaches 0 of 4/t-4/(t^2-t) ?
The limit as t approaches 0 of 4/t-4/(t^2-t) is diverges