What is the tangent of y=g(x),\at x=2 ?

The tangent of y=g(x),\at x=2 is y= d/(d2)(g(2))x+g(2)-d/(d2)(g(2))2

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tangent of y=g(x),\at x=2

tangent of

y = g (x), at x = 2

y = \frac{d}{d 2} (g (2)) x + g (2) - \frac{d}{d 2} (g (2)) 2

Solution steps

Find the tangent point:

(2, g (2))

Find the slope of

y = g (x) : \frac{d y}{d x} = \frac{d g}{d x}

Compute the slope of

y = g (x)

x = 2 : m = \frac{d}{d 2} (g (2))

Find the line with slope m=

\frac{d}{d 2} (g (2))

and passing through

(2, g (2)) : y = \frac{d}{d 2} (g (2)) x + g (2) - \frac{d}{d 2} (g (2)) 2

y = \frac{d}{d 2} (g (2)) x + g (2) - \frac{d}{d 2} (g (2)) 2

g (x) = (4 - 2 x) e^{n} - 4

\int \frac{1}{5 + 4 sin ( x )} d x

5^{2 x} x

\frac{d}{d x} (x^{4} + 4^{x})

x \to + 0 lim (\frac{e ^{- 5 x} - 1}{x})

What is the tangent of y=g(x),\at x=2 ?
The tangent of y=g(x),\at x=2 is y= d/(d2)(g(2))x+g(2)-d/(d2)(g(2))2