What is the derivative of g(x)=(4-2x)e^n-4 ?

The derivative of g(x)=(4-2x)e^n-4 is -2e^n

What is the first derivative of g(x)=(4-2x)e^n-4 ?

The first derivative of g(x)=(4-2x)e^n-4 is -2e^n

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derivative of

g (x) = (4 - 2 x) e^{n} - 4

- 2 e^{n}

Solution steps

\frac{d}{d x} ((4 - 2 x) e^{n} - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} ((4 - 2 x) e^{n}) - \frac{d}{d x} (4)

\frac{d}{d x} ((4 - 2 x) e^{n}) = - 2 e^{n}

\frac{d}{d x} (4) = 0

= - 2 e^{n} - 0

Simplify

= - 2 e^{n}

\int \frac{1}{5 + 4 sin ( x )} d x

5^{2 x} x

\frac{d}{d x} (x^{4} + 4^{x})

x \to + 0 lim (\frac{e ^{- 5 x} - 1}{x})

\frac{\partial}{\partial x} (e^{x y} + x^{2} z)

What is the derivative of g(x)=(4-2x)e^n-4 ?
The derivative of g(x)=(4-2x)e^n-4 is -2e^n
What is the first derivative of g(x)=(4-2x)e^n-4 ?
The first derivative of g(x)=(4-2x)e^n-4 is -2e^n