What is the derivative of (2x+5^7) ?

The derivative of (2x+5^7) is 14(2x+5)^6

What is the first derivative of (2x+5^7) ?

The first derivative of (2x+5^7) is 14(2x+5)^6

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\frac{d}{d x} ((2 x + 5)^{7})

14 (2 x + 5)^{6}

Solution steps

\frac{d}{d x} ((2 x + 5)^{7})

Apply the chain rule:

7 (2 x + 5)^{6} \frac{d}{d x} (2 x + 5)

= 7 (2 x + 5)^{6} \frac{d}{d x} (2 x + 5)

\frac{d}{d x} (2 x + 5) = 2

= 7 (2 x + 5)^{6} \cdot 2

Simplify

= 14 (2 x + 5)^{6}

y^{^{'}} = \frac{12 ( 2 y - 1 )}{( 3 x - 2 ) ^{2}}, y (2) = 0

\int x^{3} cos (3 x) d x

x \to + 0 lim (sin (7 x))

(5 x + 6) (6 x - 7)

\frac{d y}{d x} - (1 + x) (1 + y^{2}) = 0

What is the derivative of (2x+5^7) ?
The derivative of (2x+5^7) is 14(2x+5)^6
What is the first derivative of (2x+5^7) ?
The first derivative of (2x+5^7) is 14(2x+5)^6