What is the limit as x approaches+0 of sin(7x) ?

The limit as x approaches+0 of sin(7x) is 0

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limit as x approaches+0 of sin(7x)

x \to + 0 lim (sin (7 x))

0

Solution steps

x \to 0 lim (sin (7 x))

Plug in the value

x = 0

= sin (7 \cdot 0)

Simplify

sin (7 \cdot 0) : 0

= 0

(5 x + 6) (6 x - 7)

\frac{d y}{d x} - (1 + x) (1 + y^{2}) = 0

\int 12 + 4 x - x^{2} d x

f (x) = 2 x^{2} + 3, (- 1, 2)

x \to 2 lim (3 x^{2} - 1)

What is the limit as x approaches+0 of sin(7x) ?
The limit as x approaches+0 of sin(7x) is 0