What is the solution for (dy)/(dx)-(1+x)(1+y^2)=0 ?

The solution for (dy)/(dx)-(1+x)(1+y^2)=0 is y=tan((x^2)/2+x+c_{1})

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(dy)/(dx)-(1+x)(1+y^2)=0

\frac{d y}{d x} - (1 + x) (1 + y^{2}) = 0

y = tan (\frac{x ^{2}}{2} + x + c_{1})

Solution steps

\frac{d y}{d x} - (1 + x) (1 + y^{2}) = 0

Solve separable ODE:

y = tan (\frac{x ^{2}}{2} + x + c_{1})

y = tan (\frac{x ^{2}}{2} + x + c_{1})

\int 12 + 4 x - x^{2} d x

f (x) = 2 x^{2} + 3, (- 1, 2)

x \to 2 lim (3 x^{2} - 1)

x \to 5 + lim (\frac{x + 1}{x - 5})

f (x) = 8 e^{x} + x, at x = 8

What is the solution for (dy)/(dx)-(1+x)(1+y^2)=0 ?
The solution for (dy)/(dx)-(1+x)(1+y^2)=0 is y=tan((x^2)/2+x+c_{1})