laplacetransform e^{3t}sin(4t)

Lösung

laplace transformation

e^{3 t} sin (4 t)

\frac{4}{( s - 3 ) ^{2} + 16}

Schritte zur Lösung

L {e^{3 t} sin (4 t)}

Wende Transformationsregel an: wenn

L {f (t)} = F (s)

dann

L {e^{a t} f (t)} = F (s - a)

Für

e^{3 t} sin (4 t) : f (t) = sin (4 t), a = 3

= L {sin (4 t)} (s - 3)

L {sin (4 t)} : \frac{4}{s ^{2} + 16}

= \frac{4}{( s - 3 ) ^{2} + 16}

\int x^{2} + x d x

n = 0 \sum \infty 9^{n}

d er i v a t i v e f (x) = \frac{x ^{2}}{( x ^{3} ) ( x ^{2} )}

\int \frac{1}{x x ^{2} - 81} d x

d er i v a t i v e f (t) = t^{4} - 20 t^{3} + 112 t^{2}